It has been years that i'm not touching maths.
Today,I get this question from a friend and start doing it.
It took me such a long time and still cant come out with an answer. (-_-)lll (*shame)
Here u go, have a try ^_^
"Jim bought some chocolates and gave half of it to Ken. Ken bought some sweets and gave half of it to Jim. Jim ate 12 sweets and Ken ate 18 chocolates. The ratio of Jim’s sweets to chocolates became 1:7 and the ratio of Ken’s sweets to chocolates became 1:4. How many sweets did Ken buy?"
hao
20 years ago
6 comments:
wa.. i also blur.. hang half way.. didnt know how to count leh..
So py.. do you get the answer?
aiyo...u call eng yau to help out with u.sure he feel so easy.haha
Ya,lastly i get my answer after 3 days...oops (*shame)
This is the solution that eng yau gave to me. I laugh loudly after i saw this solution.. know why.. not understand also... hahhaahha...
let x = number of sweet
y = number of chocolate
Jim: 0.5x + 0.5y
Ken: 0.5x + 0.5y
after eating,
Jim: 0.5x - 12 : 0.5y = 1 : 7
Ken 0.5y - 18 : 0.5x = 4 : 1
solving for these equation,
Jim: 7x - 168 = y
Ken: y - 18 = 4x
7x - 168 = 4x + 18
3x = 186
x = 62
y = 4*62 + 18 = 266
62 sweets and 266 chocolate
So, is this the answer?
what they told me is sweets 68. choc i didnt count out coz the question just ask for sweets.wahaha.
This is how i did:(act i think same as eng yau)
x=sweet y= choc
So both of them having x/2 and y/2 cause half half ma.
((x/2-12)/y/2)= 1/7
((y/2-18)/x/2)= 1/4
remember that 1:7 and 1:4 just make it as 1/7 and 1/4
i think u know how to do it now,rite?
wat i got is Ken bought 56 sweets, and Jim bought 130chocolates..
but i used the total chocolates left in calculation as the ration sentence came after eating...
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